MZ11-10E300- 500RM/14D391 ROHS Intelligent PTC Type Thermistor High Sensitivity For Electronic

• Dimensions, logo, appearance and packaging

1,Dimensions

Dimensions(mm)
Dmax	F	hmax	Hmax	L	d
16.0	8.0±1.0	25.0	12.0	4.5±1.5	0.7±0.1
Note: There is a PTC thermistor between pins 1 and 2, and a varistor between pins 2 and 3.

2, Product identification

3,Packaging material and color

■ Silicone resin ■ Green

4,Lead wire

■ Tinned leads ■ Inward bend

二,Electrical performance:

• Mechanical properties:

四, Weather resistance test

Temperature characteristics

The resistance-temperature characteristics of the thermistor can be approximately expressed by the following formula: R=R0exp{B(1/T-1/T0)}: R: resistance value at temperature T(K), Ro: temperature T0, ( K) resistance value, B:B value, *T(K)=t(ºC)+273.15. In fact, the B value of the thermistor is not constant, and its variation varies depending on the material composition, and the maximum can even reach 5K/°C. Therefore, when formula 1 is applied in a larger temperature range, there will be a certain error between the measured value and the actual value. Here, if the value of B in Equation 1 is calculated as a function of temperature shown in Equation 2, the error between the measured value and the actual value can be reduced, and it can be considered to be approximately equal.

BT=CT2+DT+E, in the above formula, C, D, E are constants. In addition, the fluctuation of B value caused by different production conditions will cause the constant E to change, but the constants C and D remain unchanged. Therefore, when discussing the fluctuation of B value, only the constant E needs to be considered. Calculation of constants C, D, E, constants C, D, E can be obtained from 4 points (temperature, resistance value) data (T0, R0). (T1, R1). (T2, R2) and (T3, R3), Calculated by formulas 3-6. First, calculate B1, B2, and B3 based on the resistance values of T0 and T1, T2, and T3 from sample 3, and then substitute them into the following samples.

Calculation example of resistance value: According to the resistance-temperature characteristic table, find the resistance value of the thermistor at 25°C with a resistance value of 5 (kΩ) and a deviation of B value of 50 (K) at 10°C to 30°C. . Step (1) Calculate the constants C, D, and E according to the table of resistance-temperature characteristics. To=25+273.15T1=10+273.15T2=20+273.15T3=30+273.15 (2) Substitute BT=CT2+DT+E+50 to find BT. (3) Substitute the value into R=5exp {(BT1/T-1/298.15)} to find R. *T:10+273.15～30+273.15.

Main Feature

1. High sensitivity, its temperature coefficient of resistance is 10 to 100 times larger than that of metal, and can detect temperature changes of 10-6°C; 2, Wide operating temperature range, normal temperature devices are suitable for - 55°C to 315°C, high temperature The applicable temperature of the device is higher than 315°C (currently the highest can reach 2000°C), and the low temperature device is suitable for -273°C ~ 55°C;
3. Small in size, it can measure the temperature of gaps, cavities and blood vessels in organisms that cannot be measured by other thermometers;
4. It is easy to use, and the resistance value can be arbitrarily selected between 0.1 and 100kΩ;
5. It is easy to process into complex shapes and can be mass-produced;
6. Good stability and strong overload capacity.

Application

◆ Automotive on-board charging
◆ Discharge - charge circuits
◆ Power inverters
◆ Server power surge protection
◆ Servo motor control
◆ Welding equipment